目录
- 1、利用uuid函数生成唯一且不规则的主键id
- 2、id实现自动增长
1、利用uuid函数生成唯一且不规则的主键id
sql:
create table `test` ( `id` varchar(100) collate utf8_estonian_ci not null comment '唯一不重复', `create_time` timestamp not null default current_timestamp, `update_time` timestamp not null default current_timestamp on update current_timestamp, `sex` int(11) default null, `name` varchar(255) collate utf8_estonian_ci default null, `username` varchar(255) collate utf8_estonian_ci default null, `password` varchar(255) collate utf8_estonian_ci default null, `classes` varchar(255) collate utf8_estonian_ci default null, `major` int(255) default null, `qq` int(20) default null, `introducemyself` varchar(255) collate utf8_estonian_ci default null, primary key (`id`) ) engine=innodb default charset=utf8 collate=utf8_estonian_ci row_format=dynamic;
表:
插入语句:
insert into test(id,sex,name,username,password,classes,major,qq,introducemyself) value(replace(uuid(), '-', ''),1,"小米","xck","001","八班",265,953190259,"我最牛");
执行了俩次,生成了俩个不同id:
2、id实现自动增长
将类型改为整型,下方选择自动增长
看ddl:
create table `test` ( `id` bigint(100) not null auto_increment comment '唯一不重复', `create_time` timestamp not null default current_timestamp, `update_time` timestamp not null default current_timestamp on update current_timestamp, `sex` int(11) default null, `name` varchar(255) collate utf8_estonian_ci default null, `username` varchar(255) collate utf8_estonian_ci default null, `password` varchar(255) collate utf8_estonian_ci default null, `classes` varchar(255) collate utf8_estonian_ci default null, `major` int(255) default null, `qq` int(20) default null, `introducemyself` varchar(255) collate utf8_estonian_ci default null, primary key (`id`) ) engine=innodb default charset=utf8 collate=utf8_estonian_ci row_format=dynamic;
插入一条数据,sql:
insert into test(sex,name,username,password,classes,major,qq,introducemyself) value(1,"小米","xck","001","八班",265,953190259,"我最牛");
对应数据库变化:
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