获取MSSQL 表结构中字段的备注、主键等信息的sql

1、mssql2000


复制代码 代码如下:

select

表名 = case when a.colorder=1 then d.name else ” end,

表说明 = case when a.colorder=1 then isnull(f.value,”) else ” end,

字段序号 = a.colorder,

字段名 = a.name,

标识 = case when columnproperty( a.id,a.name,’isidentity’)=1 then ‘√’else ” end,

主键 = case when exists(select 1 from sysobjects where xtype=’pk’ and parent_obj=a.id and name in (

select name from sysindexes where indid in(

select indid from sysindexkeys where id = a.id and colid=a.colid))) then ‘√’ else ” end,

类型 = b.name,

占用字节数 = a.length,

长度 = columnproperty(a.id,a.name,’precision’),

小数位数 = isnull(columnproperty(a.id,a.name,’scale’),0),

允许空 = case when a.isnullable=1 then ‘√’else ” end,

默认值 = isnull(e.text,”),

字段说明 = isnull(g.[value],”)

from

syscolumns a

left join

systypes b

on

a.xusertype=b.xusertype

inner join

sysobjects d

on

a.id=d.id and d.xtype=’u’ and d.name<>’dtproperties’

left join

syscomments e

on

a.cdefault=e.id

left join

sysproperties g

on

a.id=g.id and a.colid=g.smallid

left join

sysproperties f

on

d.id=f.id and f.smallid=0

where

d.name=’fi_dept’ –如果只查询指定表,加上此条件

order by

a.id,a.colorder

2、mssql2005

use test–数据库

go

–2005实现字段属性统计(2000里的系统表sysproperties描述表、字段不存在,2005里用sys.extended_properties视图替代)

select

[表名]=c.name,

[表说明]=isnull(f.[value],”),

[列名]=a.name,

[列序号]=a.column_id,

[标识]=case when is_identity=1 then ‘√’ else ” end,

[主键]=case when exists(select 1 from sys.objects where parent_object_id=a.object_id and type=n’pk’ and name in

(select name from sys.indexes where index_id in

(select indid from sysindexkeys where and colid=a.column_id)))

then ‘√’ else ” end,

[类型]=b.name,

[字节数]=case when a.[max_length]=-1 and b.name!=’xml’ then ‘max/2g’

when b.name=’xml’ then ‘ 2^31-1字节/2g’

else rtrim(a.[max_length]) end,

[长度]=columnproperty(a.object_id,a.name,’precision’),

[小数]=isnull(columnproperty(a.object_id,a.name,’scale’),0),

[是否為空]=case when a.is_nullable=1 then ‘√’ else ” end,

[列说明]=isnull(e.[value],”),

[默认值]=isnull(d.text,”)

from

sys.columns a

left join

sys.types b on a.user_type_id=b.user_type_id

inner join

sys.objects c on a.object_id=c.object_id and c.type=’u’

left join

syscomments d on a.default_object_id=d.id

left join

sys.extended_properties e on e.major_id=c.object_id and e.minor_id=a.column_id and e.class=1

left join

sys.extended_properties f on f.major_id=c.object_id and f.minor_id=0 and f.class=1

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结果:

(0)
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