SQL中Group分组获取Top N方法实现可首选row_number

有产品表,包含id,name,city,addtime四个字段,因报表需要按城市分组,统计每个城市的最新10个产品,便向该表中插入了100万数据,做了如下系列测试:


复制代码 代码如下:

create table [dbo].[products](

[id] [int] identity(1,1) not null,

[name] [nvarchar](50) null,

[addtime] [datetime] null,

[city] [nvarchar](10) null,

constraint [pk_products] primary key clustered

(

[id] asc

)with (pad_index = off, statistics_norecompute = off, ignore_dup_key = off, allow_row_locks = on, allow_page_locks = on) on [primary]

) on [primary]

1、采用row_number方法,执行5次,平均下来8秒左右,速度最快。


复制代码 代码如下:

select no, id,name,city

from (select no =row_number() over (partition by city order by addtime desc), * from products)t

where no< 11 order by city asc,addtime desc

2、采用cross apply方法,执行了3次,基本都在3分5秒以上,已经很慢了。


复制代码 代码如下:

select distinct b.id,b.name,b.city from products a

cross apply (select top 10 * from products where city = a.city order by addtime desc) b

3、采用count查询,只执行了两次,第一次执行到5分钟时,取消任务执行了;第二次执行到13分钟时,没有hold住又直接停止了,实在无法忍受。


复制代码 代码如下:

select id,name,city from products a

where ( select count(city) from products where a.city = city and addtime>a.addtime) < 10

order by city asc,addtime desc

4、采用游标方法,这个最后测试的,执行了5次,每次都是10秒完成,感觉还不错。


复制代码 代码如下:

declare @city nvarchar(10)

create table #top(id int,name nvarchar(50),city nvarchar(10),addtime datetime)

declare mycursor cursor for

select distinct city from products order by city asc

open mycursor

fetch next from mycursor into @city

while @@fetch_status =0

begin

insert into #top

select top 10 id,name,city,addtime from products where city = @city

fetch next from mycursor into @city

end

close mycursor

deallocate mycursor

select * from #top order by city asc,addtime desc

drop table #top

通过上述对比不难发现,在面临group获取top n场景时,可以首选row_number,游标cursor其次,另外两个就基本不考虑了,数据量大的时候根本没法使用。

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