sql> select ktuxeusn, ktuxeslt, ktuxesqn, /* transaction id */ 2 ktuxesta status, ktuxecfl flags ,ktuxesiz 3 from x$ktuxe 4 where ktuxesta!='inactive'; ktuxeusn ktuxeslt ktuxesqn status flags ktuxesiz ---------- ---------- ---------- ---------------- ------------------------ ---------- 13 5 47447 active dead 2819919 39 0 502 active none 1 43 45 480 active none 0
sql> / ktuxeusn ktuxeslt ktuxesqn status flags ktuxesiz ---------- ---------- ---------- ---------------- ------------------------ ---------- 13 5 47447 active dead 2819919<----该值没减小。 39 0 502 active none 1 43 45 480 active none 0
查询v$px_session和v$fast_start_servers,显示很多并行进程在rollback,根据以往的工程经验:
于是改为
sql>alter system set fast_start_parallel_rollback=false scope=both;
之后,再次运行
sql> select ktuxeusn, ktuxeslt, ktuxesqn,/* transaction id */ 2 ktuxesta status, ktuxecfl flags ,ktuxesiz 3 from x$ktuxe 4 where ktuxesta!='inactive'; ktuxeusn ktuxeslt ktuxesqn status flags ktuxesiz ---------- ---------- -------------------------- ------------------------ ---------- 13 5 47447 active dead 2033516 35 29 502 active none 1 sql> / ktuxeusn ktuxeslt ktuxesqn status flags ktuxesiz ---------- ---------- -------------------------- ------------------------ ---------- 13 5 47447 active dead 2033433<---该值不断变小。 35 29 502 active none 1
使用如下脚本查看回滚完毕的预计时间(以天为单位):
sql> set serveroutput on sql> declare 2 l_start number; 3 l_end number; 4 begin 5 select ktuxesiz into l_startfrom x$ktuxe where ktuxeusn=13 and ktuxeslt=5; 6 dbms_lock.sleep(60); 7 select ktuxesiz into l_endfrom x$ktuxe where ktuxeusn=13 and ktuxeslt=5; 8 dbms_output.put_line('time estday:'|| round(l_end/(l_start -l_end)/60/24,2)); 9 end; 10 / time est day:.21
24*0.21=5.04小时。即:预计5.04小时后回滚完毕。
另外注意:在其他环境使用时,请注意替换ktuxeusn=13和ktuxeslt=5