oracle使用实例记录
显示所有在欧洲区域工作的员工，显示他们的部门，姓名，岗位，薪资，国籍，结果按照国籍升序，薪资降序排列 select d.department_name, e.last_name, e.job_id, e.salary, c.country_name
from employees e, departments d, locations l, regions r, countries c
where e.department_id = d.department_id
and d.location_id = l.location_id
and l.country_id = c.country_id
and c.region_id = r.region_id
and r.region_name = 'europe'
order by country_name, salary desc;
用尽可能多的方式显示姓名以小写’s’结尾的人员总数；至少2种方法
第一种方法 select count(*) from employees
where last_name like '%s';
第二种方法
select count(*) from employees
where substr(last_name,-1)='s'; 正则表达式 select count(*)
from employees
where regexp_like(last_name,'(*)s$');
查询所有薪资大于‘it_prog’部门任何一人的薪资员工信息，显示姓名、薪资、岗位；用2种方法实现 第一种方法 select employee_id,first_name,last_name,salary,job_id
from employees
where salary > any(select salary from employees where job_id='it_prog')
order by salary; 第二种方法 select employee_id,first_name,last_name,salary,job_id
from employees
where salary > (select min(salary)
from employees
where job_id='it_prog')
order by salary;
创建一张表与employees表相同的表，表名：employees_工号;将’marketing’，’it’ 两个部门下员工导入该表。提供脚本
create table employees_工号 as select * from employees where 1=2;
insert into employees_工号 (select * from employees
where job_id like 'it%' or job_id like 'mk%');
查询hr下所有的约束/索引 select index_name ,index_type from dba_indexes where owner='hr';